Golang encoding/xml.Encoder.Indent() function example

package encoding/xml

Indent sets the encoder to generate XML in which each element begins on a new indented line that starts with prefix and is followed by one or more copies of indent according to the nesting depth.

Golang encoding/xml.Encoder.Indent() function usage example

 package main

 import (
 "encoding/xml"
 "fmt"
 "os"
 "reflect"
 )

 type Address struct {
 City, State string
 City, State string
 }
 type Person struct {
 XMLName xml.Name `xml:"person"`
 Id int `xml:"id,attr"`
 FirstName string `xml:"name>first"`
 LastName  string `xml:"name>last"`
 Age int `xml:"age"`
 Height float32  `xml:"height,omitempty"`
 Married bool
 Address
 Comment string `xml:",comment"`
 }

 func main() {
 v := &Person{Id: 13, FirstName: "John", LastName: "Doe", Age: 42}
 v.Comment = " Need more details. "
 v.Address = Address{"Hanga Roa", "Easter Island"}

 encoder := xml.NewEncoder(os.Stdout)
 encoder.Indent(" ", " ") // <---- here

 newtoken := xml.StartElement{
 Name : xml.Name{
 Space: "",
 Local: "location",
 },
 }

 if err := encoder.EncodeToken(newtoken); err != nil {
 fmt.Println(err)
 }


 start := xml.StartElement{
 Name: xml.Name{
 Space: "",
 Local: reflect.Indirect(reflect.ValueOf(v)).Type().Name(),
 },
 Attr: []xml.Attr{{xml.Name{"", "xmlns"}, "https://socketloop.com/xmldoc/2014-09-01/"}},
 }
 if err := encoder.EncodeElement(v, start); err != nil {
 fmt.Println(err)
 }

 encoder.Flush()

 }

Reference :

http://golang.org/pkg/encoding/xml/#Encoder.Indent